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121030433002 = 260515216501
BaseRepresentation
bin111000010110111111…
…0011101100011101010
3102120101211010000211201
41300231332131203222
53440332242324002
6131333422114414
711513150464153
oct1605576354352
9376354100751
10121030433002
1147368584746
121b558a1ba0a
13b54a81b63b
145c0213692a
153235699087
hex1c2df9d8ea

121030433002 has 4 divisors (see below), whose sum is σ = 181545649506. Its totient is φ = 60515216500.

The previous prime is 121030432981. The next prime is 121030433011. The reversal of 121030433002 is 200334030121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 63368496361 + 57661936641 = 251731^2 + 240129^2 .

It is a super-2 number, since 2×1210304330022 (a number of 23 digits) contains 22 as substring.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30257608249 + ... + 30257608252.

Almost surely, 2121030433002 is an apocalyptic number.

121030433002 is a deficient number, since it is larger than the sum of its proper divisors (60515216504).

121030433002 is an equidigital number, since it uses as much as digits as its factorization.

121030433002 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 60515216503.

The product of its (nonzero) digits is 432, while the sum is 19.

Adding to 121030433002 its reverse (200334030121), we get a palindrome (321364463123).

The spelling of 121030433002 in words is "one hundred twenty-one billion, thirty million, four hundred thirty-three thousand, two".

Divisors: 1 2 60515216501 121030433002