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1210312431313 = 5932040999041
BaseRepresentation
bin10001100111001100001…
…111100001011011010001
311021201000202100220021221
4101213030033201123101
5124312204440300223
62324002043445041
7153304445631316
oct21471417413321
94251022326257
101210312431313
114273218a63a7
12176697226781
138a193c3637b
1442817d78d0d
152173a210b5d
hex119cc3e16d1

1210312431313 has 4 divisors (see below), whose sum is σ = 1212353430948. Its totient is φ = 1208271431680.

The previous prime is 1210312431259. The next prime is 1210312431457. The reversal of 1210312431313 is 3131342130121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 1015564093504 + 194748337809 = 1007752^2 + 441303^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1210312431313 is a prime.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (1210312434313) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1020498928 + ... + 1020500113.

It is an arithmetic number, because the mean of its divisors is an integer number (303088357737).

Almost surely, 21210312431313 is an apocalyptic number.

It is an amenable number.

1210312431313 is a deficient number, since it is larger than the sum of its proper divisors (2040999635).

1210312431313 is an equidigital number, since it uses as much as digits as its factorization.

1210312431313 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 2040999634.

The product of its (nonzero) digits is 1296, while the sum is 25.

Adding to 1210312431313 its reverse (3131342130121), we get a palindrome (4341654561434).

The spelling of 1210312431313 in words is "one trillion, two hundred ten billion, three hundred twelve million, four hundred thirty-one thousand, three hundred thirteen".

Divisors: 1 593 2040999041 1210312431313