Base | Representation |
---|---|
bin | 1011000000011111101011… |
… | …0010000110010101110001 |
3 | 1120212001021221221200002121 |
4 | 2300013322302012111301 |
5 | 3041244202324410001 |
6 | 41424033514314241 |
7 | 2356264565125153 |
oct | 260077262062561 |
9 | 46761257850077 |
10 | 12103130310001 |
11 | 39469aa594165 |
12 | 1435801a28981 |
13 | 69a4218aa463 |
14 | 2dbb1a686ad3 |
15 | 15ec6bd8e6a1 |
hex | b01fac86571 |
12103130310001 has 4 divisors (see below), whose sum is σ = 12136108867072. Its totient is φ = 12070151752932.
The previous prime is 12103130309939. The next prime is 12103130310053. The reversal of 12103130310001 is 10001303130121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.
It is a cyclic number.
It is not a de Polignac number, because 12103130310001 - 221 = 12103128212849 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12103130319001) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 16489277985 + ... + 16489278718.
It is an arithmetic number, because the mean of its divisors is an integer number (3034027216768).
Almost surely, 212103130310001 is an apocalyptic number.
It is an amenable number.
12103130310001 is a deficient number, since it is larger than the sum of its proper divisors (32978557071).
12103130310001 is an equidigital number, since it uses as much as digits as its factorization.
12103130310001 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 32978557070.
The product of its (nonzero) digits is 54, while the sum is 16.
Adding to 12103130310001 its reverse (10001303130121), we get a palindrome (22104433440122).
The spelling of 12103130310001 in words is "twelve trillion, one hundred three billion, one hundred thirty million, three hundred ten thousand, one".
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