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121031321010122 = 260515660505061
BaseRepresentation
bin11011100001001111001100…
…111001010011111111001010
3120212112110222212012122000102
4123201033030321103333022
5111330434121134310442
61105225004333205402
734331136651136415
oct3341171471237712
9525473885178012
10121031321010122
1135623105480636
12116a8820630862
13526c2876706a3
1421c5d39150b7c
15ded480986232
hex6e13cce53fca

121031321010122 has 4 divisors (see below), whose sum is σ = 181546981515186. Its totient is φ = 60515660505060.

The previous prime is 121031321010097. The next prime is 121031321010161. The reversal of 121031321010122 is 221010123130121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 119791908612601 + 1239412397521 = 10944949^2 + 1113289^2 .

It is a junction number, because it is equal to n+sod(n) for n = 121031321010094 and 121031321010103.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 30257830252529 + ... + 30257830252532.

Almost surely, 2121031321010122 is an apocalyptic number.

121031321010122 is a deficient number, since it is larger than the sum of its proper divisors (60515660505064).

121031321010122 is an equidigital number, since it uses as much as digits as its factorization.

121031321010122 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 60515660505063.

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121031321010122 its reverse (221010123130121), we get a palindrome (342041444140243).

The spelling of 121031321010122 in words is "one hundred twenty-one trillion, thirty-one billion, three hundred twenty-one million, ten thousand, one hundred twenty-two".

Divisors: 1 2 60515660505061 121031321010122