Base | Representation |
---|---|
bin | 10110100010110101… |
… | …10011111111100001 |
3 | 1011020111200111110110 |
4 | 23101122303333201 |
5 | 144241432321231 |
6 | 5321001521533 |
7 | 605635133445 |
oct | 132132637741 |
9 | 34214614413 |
10 | 12103401441 |
11 | 515106670a |
12 | 24194a32a9 |
13 | 11ab6c9601 |
14 | 82b656825 |
15 | 4ac898046 |
hex | 2d16b3fe1 |
12103401441 has 4 divisors (see below), whose sum is σ = 16137868592. Its totient is φ = 8068934292.
The previous prime is 12103401421. The next prime is 12103401463. The reversal of 12103401441 is 14410430121.
It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 14410430121 = 3 ⋅4803476707.
It is not a de Polignac number, because 12103401441 - 218 = 12103139297 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12103401421) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2017233571 + ... + 2017233576.
It is an arithmetic number, because the mean of its divisors is an integer number (4034467148).
Almost surely, 212103401441 is an apocalyptic number.
It is an amenable number.
12103401441 is a deficient number, since it is larger than the sum of its proper divisors (4034467151).
12103401441 is an equidigital number, since it uses as much as digits as its factorization.
12103401441 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 4034467150.
The product of its (nonzero) digits is 384, while the sum is 21.
Adding to 12103401441 its reverse (14410430121), we get a palindrome (26513831562).
The spelling of 12103401441 in words is "twelve billion, one hundred three million, four hundred one thousand, four hundred forty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.063 sec. • engine limits •