Base | Representation |
---|---|
bin | 10110100010110101… |
… | …11011110011100011 |
3 | 1011020111202010100201 |
4 | 23101122323303203 |
5 | 144241434332233 |
6 | 5321002330031 |
7 | 605635325653 |
oct | 132132736343 |
9 | 34214663321 |
10 | 12103433443 |
11 | 5151088762 |
12 | 24194b9917 |
13 | 11ab70b04a |
14 | 82b664363 |
15 | 4ac8a277d |
hex | 2d16bbce3 |
12103433443 has 4 divisors (see below), whose sum is σ = 12104703688. Its totient is φ = 12102163200.
The previous prime is 12103433437. The next prime is 12103433483. The reversal of 12103433443 is 34433430121.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 34433430121 = 61 ⋅564482461.
It is a cyclic number.
It is not a de Polignac number, because 12103433443 - 25 = 12103433411 is a prime.
It is a super-2 number, since 2×121034334432 (a number of 21 digits) contains 22 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (12103433483) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 620721 + ... + 639922.
It is an arithmetic number, because the mean of its divisors is an integer number (3026175922).
Almost surely, 212103433443 is an apocalyptic number.
12103433443 is a deficient number, since it is larger than the sum of its proper divisors (1270245).
12103433443 is an equidigital number, since it uses as much as digits as its factorization.
12103433443 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 1270244.
The product of its (nonzero) digits is 10368, while the sum is 28.
Adding to 12103433443 its reverse (34433430121), we get a palindrome (46536863564).
The spelling of 12103433443 in words is "twelve billion, one hundred three million, four hundred thirty-three thousand, four hundred forty-three".
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