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12104020131 = 37282340273
BaseRepresentation
bin10110100010111010…
…01011000010100011
31011020112211221010220
423101131023002203
5144242112121011
65321023054123
7605643321300
oct132135130243
934215757126
1012104020131
115151449525
122419741343
1311ab8850b8
1482b7780a7
154ac96b506
hex2d174b0a3

12104020131 has 12 divisors (see below), whose sum is σ = 18773582472. Its totient is φ = 6916582848.

The previous prime is 12104020079. The next prime is 12104020133. The reversal of 12104020131 is 13102040121.

It is not a de Polignac number, because 12104020131 - 217 = 12103889059 is a prime.

It is a super-2 number, since 2×121040201312 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12104020131.

It is not an unprimeable number, because it can be changed into a prime (12104020133) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41169990 + ... + 41170283.

It is an arithmetic number, because the mean of its divisors is an integer number (1564465206).

Almost surely, 212104020131 is an apocalyptic number.

12104020131 is a deficient number, since it is larger than the sum of its proper divisors (6669562341).

12104020131 is an equidigital number, since it uses as much as digits as its factorization.

12104020131 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 82340290 (or 82340283 counting only the distinct ones).

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 12104020131 its reverse (13102040121), we get a palindrome (25206060252).

The spelling of 12104020131 in words is "twelve billion, one hundred four million, twenty thousand, one hundred thirty-one".

Divisors: 1 3 7 21 49 147 82340273 247020819 576381911 1729145733 4034673377 12104020131