Base | Representation |
---|---|
bin | 1011000000100110011110… |
… | …1100010100101110101011 |
3 | 1120212020000022011011212122 |
4 | 2300021213230110232223 |
5 | 3041311423110400434 |
6 | 41424535105501455 |
7 | 2356361063110406 |
oct | 260114754245653 |
9 | 46766008134778 |
10 | 12104957512619 |
11 | 3947757a38574 |
12 | 143603194188b |
13 | 69a65330313a |
14 | 2dbc51200d3d |
15 | 15ed274bcc2e |
hex | b0267b14bab |
12104957512619 has 2 divisors, whose sum is σ = 12104957512620. Its totient is φ = 12104957512618.
The previous prime is 12104957512603. The next prime is 12104957512633. The reversal of 12104957512619 is 91621575940121.
12104957512619 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12104957512619 - 24 = 12104957512603 is a prime.
It is a super-2 number, since 2×121049575126192 (a number of 27 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (12104957512699) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6052478756309 + 6052478756310.
It is an arithmetic number, because the mean of its divisors is an integer number (6052478756310).
Almost surely, 212104957512619 is an apocalyptic number.
12104957512619 is a deficient number, since it is larger than the sum of its proper divisors (1).
12104957512619 is an equidigital number, since it uses as much as digits as its factorization.
12104957512619 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1360800, while the sum is 53.
The spelling of 12104957512619 in words is "twelve trillion, one hundred four billion, nine hundred fifty-seven million, five hundred twelve thousand, six hundred nineteen".
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