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1210536120793 is a prime number
BaseRepresentation
bin10001100111011001100…
…100110101000111011001
311021201121100021111120111
4101213121210311013121
5124313134221331133
62324040154124321
7153313133152246
oct21473144650731
94251540244514
101210536120793
1142742709963a
1217673a1206a1
138a1cb3961cc
14428399665cd
152174eb991cd
hex119d99351d9

1210536120793 has 2 divisors, whose sum is σ = 1210536120794. Its totient is φ = 1210536120792.

The previous prime is 1210536120769. The next prime is 1210536120797. The reversal of 1210536120793 is 3970216350121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 762422356224 + 448113764569 = 873168^2 + 669413^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1210536120793 is a prime.

It is not a weakly prime, because it can be changed into another prime (1210536120797) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605268060396 + 605268060397.

It is an arithmetic number, because the mean of its divisors is an integer number (605268060397).

Almost surely, 21210536120793 is an apocalyptic number.

It is an amenable number.

1210536120793 is a deficient number, since it is larger than the sum of its proper divisors (1).

1210536120793 is an equidigital number, since it uses as much as digits as its factorization.

1210536120793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 68040, while the sum is 40.

The spelling of 1210536120793 in words is "one trillion, two hundred ten billion, five hundred thirty-six million, one hundred twenty thousand, seven hundred ninety-three".