1211000102017 has 2 divisors, whose sum is σ = 1211000102018. Its totient is φ = 1211000102016.

The previous prime is 1211000101951. The next prime is 1211000102071. The reversal of 1211000102017 is 7102010001121.

Together with next prime (1211000102071) it forms an Ormiston pair, because they use the same digits, order apart.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1168061631361 + 42938470656 = 1080769^2 + 207216^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211000102017 - 2¹⁵ = 1211000069249 is a prime.

It is not a weakly prime, because it can be changed into another prime (1211000702017) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605500051008 + 605500051009.

It is an arithmetic number, because the mean of its divisors is an integer number (605500051009).

Almost surely, 2^{1211000102017} is an apocalyptic number.

It is an amenable number.

1211000102017 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211000102017 is an equidigital number, since it uses as much as digits as its factorization.

1211000102017 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 28, while the sum is 16.

Adding to 1211000102017 its reverse (7102010001121), we get a palindrome (8313010103138).

The spelling of 1211000102017 in words is "one trillion, two hundred eleven billion, one hundred two thousand, seventeen".