Base | Representation |
---|---|
bin | 10001100111110101010… |
… | …010010010001100100111 |
3 | 11021202210202001220001221 |
4 | 101213311102102030213 |
5 | 124320112230134343 |
6 | 2324154242401211 |
7 | 153330506561140 |
oct | 21476522221447 |
9 | 4252722056057 |
10 | 1211001021223 |
11 | 427645562174 |
12 | 176849960207 |
13 | 8a2737ac116 |
14 | 428815c2ac7 |
15 | 2177a8cc5ed |
hex | 119f5492327 |
1211001021223 has 16 divisors (see below), whose sum is σ = 1391571593280. Its totient is φ = 1032334387200.
The previous prime is 1211001021151. The next prime is 1211001021259. The reversal of 1211001021223 is 3221201001121.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1211001021223 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 1211001021197 and 1211001021206.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (1211001031223) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 812163 + ... + 1755451.
It is an arithmetic number, because the mean of its divisors is an integer number (86973224580).
Almost surely, 21211001021223 is an apocalyptic number.
1211001021223 is a deficient number, since it is larger than the sum of its proper divisors (180570572057).
1211001021223 is an equidigital number, since it uses as much as digits as its factorization.
1211001021223 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 944298.
The product of its (nonzero) digits is 48, while the sum is 16.
Adding to 1211001021223 its reverse (3221201001121), we get a palindrome (4432202022344).
The spelling of 1211001021223 in words is "one trillion, two hundred eleven billion, one million, twenty-one thousand, two hundred twenty-three".
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