121102020100121 has 2 divisors, whose sum is σ = 121102020100122. Its totient is φ = 121102020100120.

The previous prime is 121102020100097. The next prime is 121102020100133. The reversal of 121102020100121 is 121001020201121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 73445088540121 + 47656931560000 = 8570011^2 + 6903400^2 .

It is an emirp because it is prime and its reverse (121001020201121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-121102020100121 is a prime.

It is a super-3 number, since 3×121102020100121³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a junction number, because it is equal to n+sod(n) for n = 121102020100096 and 121102020100105.

It is not a weakly prime, because it can be changed into another prime (121102020120121) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60551010050060 + 60551010050061.

It is an arithmetic number, because the mean of its divisors is an integer number (60551010050061).

Almost surely, 2^{121102020100121} is an apocalyptic number.

It is an amenable number.

121102020100121 is a deficient number, since it is larger than the sum of its proper divisors (1).

121102020100121 is an equidigital number, since it uses as much as digits as its factorization.

121102020100121 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 16, while the sum is 14.

Adding to 121102020100121 its reverse (121001020201121), we get a palindrome (242103040301242).

The spelling of 121102020100121 in words is "one hundred twenty-one trillion, one hundred two billion, twenty million, one hundred thousand, one hundred twenty-one".