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12110220122001 = 34036740040667
BaseRepresentation
bin1011000000111010000101…
…0111100101011110010001
31120212201121001200102210020
42300032201113211132101
53041403212322401001
641431205221454053
72356635354415041
oct260164127453621
946781531612706
1012110220122001
113949a08600921
121437060271329
1369acb169a8a1
142dc1d0101721
151600344e9736
hexb03a15e5791

12110220122001 has 4 divisors (see below), whose sum is σ = 16146960162672. Its totient is φ = 8073480081332.

The previous prime is 12110220121963. The next prime is 12110220122003. The reversal of 12110220122001 is 10022102201121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12110220122001 - 223 = 12110211733393 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12110220122003) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018370020331 + ... + 2018370020336.

It is an arithmetic number, because the mean of its divisors is an integer number (4036740040668).

Almost surely, 212110220122001 is an apocalyptic number.

It is an amenable number.

12110220122001 is a deficient number, since it is larger than the sum of its proper divisors (4036740040671).

12110220122001 is an equidigital number, since it uses as much as digits as its factorization.

12110220122001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4036740040670.

The product of its (nonzero) digits is 32, while the sum is 15.

Adding to 12110220122001 its reverse (10022102201121), we get a palindrome (22132322323122).

The spelling of 12110220122001 in words is "twelve trillion, one hundred ten billion, two hundred twenty million, one hundred twenty-two thousand, one".

Divisors: 1 3 4036740040667 12110220122001