Base | Representation |
---|---|
bin | 10001100111111011001… |
… | …100010011010010101001 |
3 | 11021210001122112102201221 |
4 | 101213323030103102221 |
5 | 124320313112204022 |
6 | 2324212142342041 |
7 | 153333122063452 |
oct | 21477314232251 |
9 | 4253048472657 |
10 | 1211100116137 |
11 | 42769649569a |
12 | 176876b8a921 |
13 | 8a28b196972 |
14 | 4289081a129 |
15 | 21784453cc7 |
hex | 119fb3134a9 |
1211100116137 has 2 divisors, whose sum is σ = 1211100116138. Its totient is φ = 1211100116136.
The previous prime is 1211100116059. The next prime is 1211100116141. The reversal of 1211100116137 is 7316110011121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1198983390361 + 12116725776 = 1094981^2 + 110076^2 .
It is a cyclic number.
It is not a de Polignac number, because 1211100116137 - 223 = 1211091727529 is a prime.
It is not a weakly prime, because it can be changed into another prime (1211100116437) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605550058068 + 605550058069.
It is an arithmetic number, because the mean of its divisors is an integer number (605550058069).
Almost surely, 21211100116137 is an apocalyptic number.
It is an amenable number.
1211100116137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1211100116137 is an equidigital number, since it uses as much as digits as its factorization.
1211100116137 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 252, while the sum is 25.
Adding to 1211100116137 its reverse (7316110011121), we get a palindrome (8527210127258).
The spelling of 1211100116137 in words is "one trillion, two hundred eleven billion, one hundred million, one hundred sixteen thousand, one hundred thirty-seven".
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