Base | Representation |
---|---|
bin | 1011000000111101000010… |
… | …0101001010010101111011 |
3 | 1120212210122021010200022101 |
4 | 2300033100211022111323 |
5 | 3041411323111210133 |
6 | 41431415555004231 |
7 | 2356664113146445 |
oct | 260172045122573 |
9 | 46783567120271 |
10 | 12111012210043 |
11 | 394a28472833a |
12 | 1437241599677 |
13 | 69b0a9810436 |
14 | 2dc2673ab495 |
15 | 16007dd0c37d |
hex | b03d094a57b |
12111012210043 has 2 divisors, whose sum is σ = 12111012210044. Its totient is φ = 12111012210042.
The previous prime is 12111012209999. The next prime is 12111012210047. The reversal of 12111012210043 is 34001221011121.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 12111012210043 - 213 = 12111012201851 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 12111012210043.
It is not a weakly prime, because it can be changed into another prime (12111012210047) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055506105021 + 6055506105022.
It is an arithmetic number, because the mean of its divisors is an integer number (6055506105022).
Almost surely, 212111012210043 is an apocalyptic number.
12111012210043 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111012210043 is an equidigital number, since it uses as much as digits as its factorization.
12111012210043 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 12111012210043 its reverse (34001221011121), we get a palindrome (46112233221164).
The spelling of 12111012210043 in words is "twelve trillion, one hundred eleven billion, twelve million, two hundred ten thousand, forty-three".
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