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12111022011097 is a prime number
BaseRepresentation
bin1011000000111101000100…
…1010100011001011011001
31120212210122221120121211101
42300033101022203023121
53041411333113323342
641431420545031401
72356664262360112
oct260172112431331
946783587517741
1012111022011097
11394a28a211a89
121437244925561
1369b0ab862589
142dc2687dd209
1516007eae63b7
hexb03d12a32d9

12111022011097 has 2 divisors, whose sum is σ = 12111022011098. Its totient is φ = 12111022011096.

The previous prime is 12111022011091. The next prime is 12111022011191. The reversal of 12111022011097 is 79011022011121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 9942645014416 + 2168376996681 = 3153196^2 + 1472541^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-12111022011097 is a prime.

It is a super-2 number, since 2×121110220110972 (a number of 27 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12111022011091) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055511005548 + 6055511005549.

It is an arithmetic number, because the mean of its divisors is an integer number (6055511005549).

Almost surely, 212111022011097 is an apocalyptic number.

It is an amenable number.

12111022011097 is a deficient number, since it is larger than the sum of its proper divisors (1).

12111022011097 is an equidigital number, since it uses as much as digits as its factorization.

12111022011097 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 504, while the sum is 28.

The spelling of 12111022011097 in words is "twelve trillion, one hundred eleven billion, twenty-two million, eleven thousand, ninety-seven".