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1211110201993 is a prime number
BaseRepresentation
bin10001100111111011110…
…010110001101010001001
311021210002100111211221011
4101213323302301222021
5124320323202430433
62324213142443521
7153333303601336
oct21477362615211
94253070454834
101211110201993
114276a115430a
1217687a4335a1
138a2902b8623
1442891cc398d
15217852973cd
hex119fbcb1a89

1211110201993 has 2 divisors, whose sum is σ = 1211110201994. Its totient is φ = 1211110201992.

The previous prime is 1211110201963. The next prime is 1211110202041. The reversal of 1211110201993 is 3991020111121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1105509250624 + 105600951369 = 1051432^2 + 324963^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1211110201993 is a prime.

It is a super-2 number, since 2×12111102019932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1211110201913) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605555100996 + 605555100997.

It is an arithmetic number, because the mean of its divisors is an integer number (605555100997).

Almost surely, 21211110201993 is an apocalyptic number.

It is an amenable number.

1211110201993 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211110201993 is an equidigital number, since it uses as much as digits as its factorization.

1211110201993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 972, while the sum is 31.

The spelling of 1211110201993 in words is "one trillion, two hundred eleven billion, one hundred ten million, two hundred one thousand, nine hundred ninety-three".