Base | Representation |
---|---|
bin | 11011100010011001100000… |
… | …000110110110001100000011 |
3 | 120212211002220210212102010111 |
4 | 123202121200012312030003 |
5 | 111333241013124021123 |
6 | 1105325401002412151 |
7 | 34336662652214464 |
oct | 3342314006661403 |
9 | 525732823772114 |
10 | 121111100220163 |
11 | 35653a24794979 |
12 | 11700186501057 |
13 | 527695cb1c351 |
14 | 21c9b46854d6b |
15 | e0059e89090d |
hex | 6e26601b6303 |
121111100220163 has 2 divisors, whose sum is σ = 121111100220164. Its totient is φ = 121111100220162.
The previous prime is 121111100220157. The next prime is 121111100220211. The reversal of 121111100220163 is 361022001111121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 121111100220163 - 221 = 121111098123011 is a prime.
It is not a weakly prime, because it can be changed into another prime (121111100220763) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60555550110081 + 60555550110082.
It is an arithmetic number, because the mean of its divisors is an integer number (60555550110082).
Almost surely, 2121111100220163 is an apocalyptic number.
121111100220163 is a deficient number, since it is larger than the sum of its proper divisors (1).
121111100220163 is an equidigital number, since it uses as much as digits as its factorization.
121111100220163 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 144, while the sum is 22.
Adding to 121111100220163 its reverse (361022001111121), we get a palindrome (482133101331284).
The spelling of 121111100220163 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred million, two hundred twenty thousand, one hundred sixty-three".
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