Search a number
-
+
121111102099993 is a prime number
BaseRepresentation
bin11011100010011001100000…
…001110000001001000011001
3120212211002220221101220202211
4123202121200032001020121
5111333241014114144433
61105325401110555121
734336663004204155
oct3342314016011031
9525732827356684
10121111102099993
1135653a25859255
1211700187068aa1
135276960329b85
1421c9b46bc4065
15e0059eb128cd
hex6e2660381219

121111102099993 has 2 divisors, whose sum is σ = 121111102099994. Its totient is φ = 121111102099992.

The previous prime is 121111102099937. The next prime is 121111102100017. The reversal of 121111102099993 is 399990201111121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 64041734801664 + 57069367298329 = 8002608^2 + 7554427^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-121111102099993 is a prime.

It is not a weakly prime, because it can be changed into another prime (121111102799993) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60555551049996 + 60555551049997.

It is an arithmetic number, because the mean of its divisors is an integer number (60555551049997).

Almost surely, 2121111102099993 is an apocalyptic number.

It is an amenable number.

121111102099993 is a deficient number, since it is larger than the sum of its proper divisors (1).

121111102099993 is an equidigital number, since it uses as much as digits as its factorization.

121111102099993 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 78732, while the sum is 49.

The spelling of 121111102099993 in words is "one hundred twenty-one trillion, one hundred eleven billion, one hundred two million, ninety-nine thousand, nine hundred ninety-three".