Base | Representation |
---|---|
bin | 10001100111111100011… |
… | …100011011001011101011 |
3 | 11021210010010001112121000 |
4 | 101213330130123023223 |
5 | 124320334001314404 |
6 | 2324214212450043 |
7 | 153333465443241 |
oct | 21477434331353 |
9 | 4253103045530 |
10 | 1211121119979 |
11 | 4276a7331141 |
12 | 176882019923 |
13 | 8a29263bc84 |
14 | 42893526791 |
15 | 21786202339 |
hex | 119fc71b2eb |
1211121119979 has 32 divisors (see below), whose sum is σ = 1888827494400. Its totient is φ = 764862069600.
The previous prime is 1211121119947. The next prime is 1211121119983. The reversal of 1211121119979 is 9799111211121.
It is not a de Polignac number, because 1211121119979 - 25 = 1211121119947 is a prime.
It is a super-4 number, since 4×12111211199794 (a number of 49 digits) contains 4444 as substring.
It is not an unprimeable number, because it can be changed into a prime (1211121119939) by changing a digit.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 7503829 + ... + 7663529.
It is an arithmetic number, because the mean of its divisors is an integer number (59025859200).
Almost surely, 21211121119979 is an apocalyptic number.
1211121119979 is a gapful number since it is divisible by the number (19) formed by its first and last digit.
1211121119979 is a deficient number, since it is larger than the sum of its proper divisors (677706374421).
1211121119979 is a wasteful number, since it uses less digits than its factorization.
1211121119979 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 174512 (or 174506 counting only the distinct ones).
The product of its digits is 20412, while the sum is 45.
The spelling of 1211121119979 in words is "one trillion, two hundred eleven billion, one hundred twenty-one million, one hundred nineteen thousand, nine hundred seventy-nine".
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