Base | Representation |
---|---|
bin | 1011000000111101110001… |
… | …1111110001000000101001 |
3 | 1120212211011012022021011121 |
4 | 2300033130133301000221 |
5 | 3041412230300402103 |
6 | 41431451455455241 |
7 | 2360002061316544 |
oct | 260173437610051 |
9 | 46784135267147 |
10 | 12111212122153 |
11 | 394a377560261 |
12 | 1437298527521 |
13 | 69b10c066721 |
14 | 2dc285b6985b |
15 | 16009164a6bd |
hex | b03dc7f1029 |
12111212122153 has 2 divisors, whose sum is σ = 12111212122154. Its totient is φ = 12111212122152.
The previous prime is 12111212122111. The next prime is 12111212122157. The reversal of 12111212122153 is 35122121211121.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 11987992167424 + 123219954729 = 3462368^2 + 351027^2 .
It is a cyclic number.
It is not a de Polignac number, because 12111212122153 - 213 = 12111212113961 is a prime.
It is not a weakly prime, because it can be changed into another prime (12111212122157) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6055606061076 + 6055606061077.
It is an arithmetic number, because the mean of its divisors is an integer number (6055606061077).
Almost surely, 212111212122153 is an apocalyptic number.
It is an amenable number.
12111212122153 is a deficient number, since it is larger than the sum of its proper divisors (1).
12111212122153 is an equidigital number, since it uses as much as digits as its factorization.
12111212122153 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 480, while the sum is 25.
Adding to 12111212122153 its reverse (35122121211121), we get a palindrome (47233333333274).
The spelling of 12111212122153 in words is "twelve trillion, one hundred eleven billion, two hundred twelve million, one hundred twenty-two thousand, one hundred fifty-three".
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