Base | Representation |
---|---|
bin | 11011100010011010011101… |
… | …101010101000111010001100 |
3 | 120212211012120210020201201221 |
4 | 123202122131222220322030 |
5 | 111333300122022410012 |
6 | 1105330051255013124 |
7 | 34340030362625632 |
oct | 3342323552507214 |
9 | 525735523221657 |
10 | 121112133013132 |
11 | 35654404776588 |
12 | 1170041436a1a4 |
13 | 5276a95a9b851 |
14 | 21c9c03a9b352 |
15 | e0061039d507 |
hex | 6e269daa8e8c |
121112133013132 has 12 divisors (see below), whose sum is σ = 212120387451000. Its totient is φ = 60506308027136.
The previous prime is 121112133013063. The next prime is 121112133013153. The reversal of 121112133013132 is 231310331211121.
It is a super-2 number, since 2×1211121330131322 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 121112133013097 and 121112133013106.
It is an unprimeable number.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 12439614382 + ... + 12439624117.
It is an arithmetic number, because the mean of its divisors is an integer number (17676698954250).
Almost surely, 2121112133013132 is an apocalyptic number.
It is an amenable number.
121112133013132 is a deficient number, since it is larger than the sum of its proper divisors (91008254437868).
121112133013132 is a wasteful number, since it uses less digits than its factorization.
121112133013132 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 24879239720 (or 24879239718 counting only the distinct ones).
The product of its (nonzero) digits is 648, while the sum is 25.
Adding to 121112133013132 its reverse (231310331211121), we get a palindrome (352422464224253).
The spelling of 121112133013132 in words is "one hundred twenty-one trillion, one hundred twelve billion, one hundred thirty-three million, thirteen thousand, one hundred thirty-two".
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