12111301113 has 4 divisors (see below), whose sum is σ = 16148401488. Its totient is φ = 8074200740.

The previous prime is 12111301099. The next prime is 12111301127. The reversal of 12111301113 is 31110311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is an interprime number because it is at equal distance from previous prime (12111301099) and next prime (12111301127).

It is a cyclic number.

It is not a de Polignac number, because 12111301113 - 2⁸ = 12111300857 is a prime.

It is a super-2 number, since 2×12111301113² (a number of 21 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 12111301092 and 12111301101.

It is not an unprimeable number, because it can be changed into a prime (12111305113) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2018550183 + ... + 2018550188.

It is an arithmetic number, because the mean of its divisors is an integer number (4037100372).

Almost surely, 2^12111301113 is an apocalyptic number.

It is an amenable number.

12111301113 is a deficient number, since it is larger than the sum of its proper divisors (4037100375).

12111301113 is an equidigital number, since it uses as much as digits as its factorization.

12111301113 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 4037100374.

The product of its (nonzero) digits is 18, while the sum is 15.

Adding to 12111301113 its reverse (31110311121), we get a palindrome (43221612234).

The spelling of 12111301113 in words is "twelve billion, one hundred eleven million, three hundred one thousand, one hundred thirteen".