Base | Representation |
---|---|
bin | 11011100010011011010010… |
… | …101001111001011011110001 |
3 | 120212211021212202001111201101 |
4 | 123202123102221321123301 |
5 | 111333303432113323441 |
6 | 1105330315413204401 |
7 | 34340061406162540 |
oct | 3342332251713361 |
9 | 525737782044641 |
10 | 121113022011121 |
11 | 35654820573968 |
12 | 11700622030701 |
13 | 5276ba801256a |
14 | 21c9c89b92157 |
15 | e00663455231 |
hex | 6e26d2a796f1 |
121113022011121 has 8 divisors (see below), whose sum is σ = 138415432952960. Its totient is φ = 103810748732928.
The previous prime is 121113022011097. The next prime is 121113022011139. The reversal of 121113022011121 is 121110220311121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121113022011121 - 29 = 121113022010609 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121113023011121) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 32523741 + ... + 36055786.
It is an arithmetic number, because the mean of its divisors is an integer number (17301929119120).
Almost surely, 2121113022011121 is an apocalyptic number.
It is an amenable number.
121113022011121 is a deficient number, since it is larger than the sum of its proper divisors (17302410941839).
121113022011121 is an equidigital number, since it uses as much as digits as its factorization.
121113022011121 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 68831823.
The product of its (nonzero) digits is 48, while the sum is 19.
Adding to 121113022011121 its reverse (121110220311121), we get a palindrome (242223242322242).
The spelling of 121113022011121 in words is "one hundred twenty-one trillion, one hundred thirteen billion, twenty-two million, eleven thousand, one hundred twenty-one".
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