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121113023113217 is a prime number
BaseRepresentation
bin11011100010011011010010…
…101110000110100000000001
3120212211021212211010111111202
4123202123102232012200001
5111333303432404110332
61105330315452550545
734340061421432622
oct3342332256064001
9525737784114452
10121113023113217
1135654821156993
1211700622482455
135276ba830a0a5
1421c9c89d9ba49
15e006635c1a62
hex6e26d2b86801

121113023113217 has 2 divisors, whose sum is σ = 121113023113218. Its totient is φ = 121113023113216.

The previous prime is 121113023113177. The next prime is 121113023113223. The reversal of 121113023113217 is 712311320311121.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 81252033748081 + 39860989365136 = 9013991^2 + 6313556^2 .

It is a cyclic number.

It is not a de Polignac number, because 121113023113217 - 220 = 121113022064641 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 121113023113217.

It is not a weakly prime, because it can be changed into another prime (121113023113297) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60556511556608 + 60556511556609.

It is an arithmetic number, because the mean of its divisors is an integer number (60556511556609).

Almost surely, 2121113023113217 is an apocalyptic number.

It is an amenable number.

121113023113217 is a deficient number, since it is larger than the sum of its proper divisors (1).

121113023113217 is an equidigital number, since it uses as much as digits as its factorization.

121113023113217 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1512, while the sum is 29.

Adding to 121113023113217 its reverse (712311320311121), we get a palindrome (833424343424338).

The spelling of 121113023113217 in words is "one hundred twenty-one trillion, one hundred thirteen billion, twenty-three million, one hundred thirteen thousand, two hundred seventeen".