12111331023001 has 4 divisors (see below), whose sum is σ = 13841521169152. Its totient is φ = 10381140876852.

The previous prime is 12111331022951. The next prime is 12111331023013. The reversal of 12111331023001 is 10032013311121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12111331023001 is a prime.

It is a Duffinian number.

It is a self number, because there is not a number n which added to its sum of digits gives 12111331023001.

It is not an unprimeable number, because it can be changed into a prime (12111331023401) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 865095073065 + ... + 865095073078.

It is an arithmetic number, because the mean of its divisors is an integer number (3460380292288).

Almost surely, 2^{12111331023001} is an apocalyptic number.

It is an amenable number.

12111331023001 is a deficient number, since it is larger than the sum of its proper divisors (1730190146151).

12111331023001 is an equidigital number, since it uses as much as digits as its factorization.

12111331023001 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1730190146150.

The product of its (nonzero) digits is 108, while the sum is 19.

Adding to 12111331023001 its reverse (10032013311121), we get a palindrome (22143344334122).

The spelling of 12111331023001 in words is "twelve trillion, one hundred eleven billion, three hundred thirty-one million, twenty-three thousand, one".