1211142343442 has 4 divisors (see below), whose sum is σ = 1816713515166. Its totient is φ = 605571171720.

The previous prime is 1211142343429. The next prime is 1211142343459. The reversal of 1211142343442 is 2443432411121.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 628501713961 + 582640629481 = 792781^2 + 763309^2 .

It is a super-4 number, since 4×1211142343442⁴ (a number of 49 digits) contains 4444 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1211142343399 and 1211142343408.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302785585859 + ... + 302785585862.

Almost surely, 2^{1211142343442} is an apocalyptic number.

1211142343442 is a deficient number, since it is larger than the sum of its proper divisors (605571171724).

1211142343442 is an equidigital number, since it uses as much as digits as its factorization.

1211142343442 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 605571171723.

The product of its digits is 18432, while the sum is 32.

Adding to 1211142343442 its reverse (2443432411121), we get a palindrome (3654574754563).

The spelling of 1211142343442 in words is "one trillion, two hundred eleven billion, one hundred forty-two million, three hundred forty-three thousand, four hundred forty-two".