Base | Representation |
---|---|
bin | 11011100010100111001110… |
… | …000001101000100001101110 |
3 | 120212212111221022010121110000 |
4 | 123202213032001220201232 |
5 | 111334011144241433014 |
6 | 1105340234320525130 |
7 | 34341023652000063 |
oct | 3342471601504156 |
9 | 525774838117400 |
10 | 121125829249134 |
11 | 3565a1a295a396 |
12 | 11702bb71807a6 |
13 | 52781694925c8 |
14 | 21ca742aa0c6a |
15 | e00b629cc509 |
hex | 6e29ce06886e |
121125829249134 has 20 divisors (see below), whose sum is σ = 271411580354904. Its totient is φ = 40375276416324.
The previous prime is 121125829249081. The next prime is 121125829249157. The reversal of 121125829249134 is 431942928521121.
121125829249134 is a `hidden beast` number, since 1 + 2 + 1 + 1 + 2 + 582 + 9 + 2 + 49 + 13 + 4 = 666.
It is a super-2 number, since 2×1211258292491342 (a number of 29 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (54).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 9 ways as a sum of consecutive naturals, for example, 373845151842 + ... + 373845152165.
Almost surely, 2121125829249134 is an apocalyptic number.
121125829249134 is an abundant number, since it is smaller than the sum of its proper divisors (150285751105770).
It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.
121125829249134 is an equidigital number, since it uses as much as digits as its factorization.
121125829249134 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 747690304021 (or 747690304012 counting only the distinct ones).
The product of its digits is 2488320, while the sum is 54.
The spelling of 121125829249134 in words is "one hundred twenty-one trillion, one hundred twenty-five billion, eight hundred twenty-nine million, two hundred forty-nine thousand, one hundred thirty-four".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.074 sec. • engine limits •