121130010131121 has 24 divisors (see below), whose sum is σ = 181517128490880. Its totient is φ = 80721584528112.

The previous prime is 121130010131113. The next prime is 121130010131129. The reversal of 121130010131121 is 121131010031121.

121130010131121 is a `hidden beast` number, since 1 + 21 + 1 + 300 + 10 + 1 + 311 + 21 = 666.

It is an interprime number because it is at equal distance from previous prime (121130010131113) and next prime (121130010131129).

It is not a de Polignac number, because 121130010131121 - 2³ = 121130010131113 is a prime.

It is a super-2 number, since 2×121130010131121² (a number of 29 digits) contains 22 as substring.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121130010131094 and 121130010131103.

It is not an unprimeable number, because it can be changed into a prime (121130010131129) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 97391766 + ... + 98627663.

It is an arithmetic number, because the mean of its divisors is an integer number (7563213687120).

Almost surely, 2^{121130010131121} is an apocalyptic number.

It is an amenable number.

121130010131121 is a deficient number, since it is larger than the sum of its proper divisors (60387118359759).

121130010131121 is an equidigital number, since it uses as much as digits as its factorization.

121130010131121 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 196021987 (or 196021975 counting only the distinct ones).

The product of its (nonzero) digits is 36, while the sum is 18.

Adding to 121130010131121 its reverse (121131010031121), we get a palindrome (242261020162242).

The spelling of 121130010131121 in words is "one hundred twenty-one trillion, one hundred thirty billion, ten million, one hundred thirty-one thousand, one hundred twenty-one".