1211302229953 has 2 divisors, whose sum is σ = 1211302229954. Its totient is φ = 1211302229952.

The previous prime is 1211302229941. The next prime is 1211302229971. The reversal of 1211302229953 is 3599222031121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 756712091664 + 454590138289 = 869892^2 + 674233^2 .

It is a cyclic number.

It is not a de Polignac number, because 1211302229953 - 2²⁵ = 1211268675521 is a prime.

It is a super-3 number, since 3×1211302229953³ (a number of 37 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not a weakly prime, because it can be changed into another prime (1211302229923) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 605651114976 + 605651114977.

It is an arithmetic number, because the mean of its divisors is an integer number (605651114977).

Almost surely, 2^{1211302229953} is an apocalyptic number.

It is an amenable number.

1211302229953 is a deficient number, since it is larger than the sum of its proper divisors (1).

1211302229953 is an equidigital number, since it uses as much as digits as its factorization.

1211302229953 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 58320, while the sum is 40.

The spelling of 1211302229953 in words is "one trillion, two hundred eleven billion, three hundred two million, two hundred twenty-nine thousand, nine hundred fifty-three".