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121130313000000 = 26356107377353
BaseRepresentation
bin11011100010101011011001…
…010001110010010001000000
3120212212221111210002202022220
4123202223121101302101000
5111334044340112000000
61105342255251131040
734341243035153043
oct3342533121622100
9525787453082286
10121130313000000
1135661093911817
1211703a488a3a80
13527870239a025
1421caa4a37ac5a
15e00d2645b1a0
hex6e2ad9472440

121130313000000 has 392 divisors, whose sum is σ = 404353219837536. Its totient is φ = 31999449600000.

The previous prime is 121130312999989. The next prime is 121130313000013. The reversal of 121130313000000 is 313031121.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 320811324 + ... + 321188676.

Almost surely, 2121130313000000 is an apocalyptic number.

121130313000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 121130313000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (202176609918768).

121130313000000 is an abundant number, since it is smaller than the sum of its proper divisors (283222906837536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

121130313000000 is an frugal number, since it uses more digits than its factorization.

121130313000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 377505 (or 377470 counting only the distinct ones).

The product of its (nonzero) digits is 54, while the sum is 15.

Adding to 121130313000000 its reverse (313031121), we get a palindrome (121130626031121).

The spelling of 121130313000000 in words is "one hundred twenty-one trillion, one hundred thirty billion, three hundred thirteen million", and thus it is an aban number.