12113122119953 has 2 divisors, whose sum is σ = 12113122119954. Its totient is φ = 12113122119952.

The previous prime is 12113122119919. The next prime is 12113122120019. The reversal of 12113122119953 is 35991122131121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 12098070019984 + 15052099969 = 3478228^2 + 122687^2 .

It is an emirp because it is prime and its reverse (35991122131121) is a distict prime.

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-12113122119953 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 12113122119953.

It is not a weakly prime, because it can be changed into another prime (12113122119053) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6056561059976 + 6056561059977.

It is an arithmetic number, because the mean of its divisors is an integer number (6056561059977).

Almost surely, 2^{12113122119953} is an apocalyptic number.

It is an amenable number.

12113122119953 is a deficient number, since it is larger than the sum of its proper divisors (1).

12113122119953 is an equidigital number, since it uses as much as digits as its factorization.

12113122119953 is an evil number, because the sum of its binary digits is even.

The product of its digits is 29160, while the sum is 41.

The spelling of 12113122119953 in words is "twelve trillion, one hundred thirteen billion, one hundred twenty-two million, one hundred nineteen thousand, nine hundred fifty-three".