Base | Representation |
---|---|
bin | 11011100010101110001100… |
… | …101001011001010111001001 |
3 | 120212220020021111122121010001 |
4 | 123202232030221121113021 |
5 | 111334122021002423423 |
6 | 1105343514031123001 |
7 | 34341410435655610 |
oct | 3342561451312711 |
9 | 525806244577101 |
10 | 121133322311113 |
11 | 356623985617a2 |
12 | 11704548673461 |
13 | 5278a919916a8 |
14 | 21cac53cc8877 |
15 | e00e5073dcad |
hex | 6e2b8ca595c9 |
121133322311113 has 8 divisors (see below), whose sum is σ = 138618106161920. Its totient is φ = 103693544340480.
The previous prime is 121133322311083. The next prime is 121133322311117. The reversal of 121133322311113 is 311113223331121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121133322311113 - 29 = 121133322310601 is a prime.
It is not an unprimeable number, because it can be changed into a prime (121133322311117) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 11251464273 + ... + 11251475038.
It is an arithmetic number, because the mean of its divisors is an integer number (17327263270240).
Almost surely, 2121133322311113 is an apocalyptic number.
It is an amenable number.
121133322311113 is a deficient number, since it is larger than the sum of its proper divisors (17484783850807).
121133322311113 is an equidigital number, since it uses as much as digits as its factorization.
121133322311113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 22502940087.
The product of its digits is 1944, while the sum is 28.
Adding to 121133322311113 its reverse (311113223331121), we get a palindrome (432246545642234).
The spelling of 121133322311113 in words is "one hundred twenty-one trillion, one hundred thirty-three billion, three hundred twenty-two million, three hundred eleven thousand, one hundred thirteen".
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