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12113414305 = 5127167114229
BaseRepresentation
bin10110100100000010…
…00000100010100001
31011021012112012112021
423102001000202201
5144302013224210
65322000301441
7606116215456
oct132201004241
934235465467
1012113414305
115156785503
122420911881
1311b07c3c95
1482cb0182d
154ad6c4bda
hex2d20408a1

12113414305 has 16 divisors (see below), whose sum is σ = 14738411520. Its totient is φ = 9556771392.

The previous prime is 12113414281. The next prime is 12113414317. The reversal of 12113414305 is 50341431121.

It is not a de Polignac number, because 12113414305 - 25 = 12113414273 is a prime.

It is a super-2 number, since 2×121134143052 (a number of 21 digits) contains 22 as substring.

It is a self number, because there is not a number n which added to its sum of digits gives 12113414305.

It is an unprimeable number.

It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 48931 + ... + 163159.

It is an arithmetic number, because the mean of its divisors is an integer number (921150720).

Almost surely, 212113414305 is an apocalyptic number.

It is an amenable number.

12113414305 is a deficient number, since it is larger than the sum of its proper divisors (2624997215).

12113414305 is a wasteful number, since it uses less digits than its factorization.

12113414305 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 114528.

The product of its (nonzero) digits is 1440, while the sum is 25.

Adding to 12113414305 its reverse (50341431121), we get a palindrome (62454845426).

The spelling of 12113414305 in words is "twelve billion, one hundred thirteen million, four hundred fourteen thousand, three hundred five".

Divisors: 1 5 127 167 635 835 21209 106045 114229 571145 14507083 19076243 72535415 95381215 2422682861 12113414305