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12113445501051 = 35121778837401
BaseRepresentation
bin1011000001000110000110…
…0111011011100001111011
31120220000220211210200001120
42300101201213123201323
53041431314022013201
641432501240520323
72360111320606356
oct260214147334173
946800824720046
1012113445501051
113950313208944
1214378004800a3
1369b3a6983cbb
142dc41861529d
1516017275c536
hexb04619db87b

12113445501051 has 8 divisors (see below), whose sum is σ = 16151576222544. Its totient is φ = 8075472556800.

The previous prime is 12113445500993. The next prime is 12113445501067. The reversal of 12113445501051 is 15010554431121.

12113445501051 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.

It is a sphenic number, since it is the product of 3 distinct primes.

It is not a de Polignac number, because 12113445501051 - 215 = 12113445468283 is a prime.

It is not an unprimeable number, because it can be changed into a prime (12113445501151) by changing a digit.

It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 39265050 + ... + 39572351.

It is an arithmetic number, because the mean of its divisors is an integer number (2018947027818).

Almost surely, 212113445501051 is an apocalyptic number.

12113445501051 is a deficient number, since it is larger than the sum of its proper divisors (4038130721493).

12113445501051 is an equidigital number, since it uses as much as digits as its factorization.

12113445501051 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 78888621.

The product of its (nonzero) digits is 12000, while the sum is 33.

Adding to 12113445501051 its reverse (15010554431121), we get a palindrome (27123999932172).

The spelling of 12113445501051 in words is "twelve trillion, one hundred thirteen billion, four hundred forty-five million, five hundred one thousand, fifty-one".

Divisors: 1 3 51217 153651 78837401 236512203 4037815167017 12113445501051