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121135065407987 is a prime number
BaseRepresentation
bin11011100010101111110100…
…100010110010000111110011
3120212220101202222121002111112
4123202233310202302013303
5111334134103221023422
61105344403015503535
734341501563024651
oct3342576442620763
9525811688532445
10121135065407987
1135663102490224
1211704954387bab
135278cabb4a267
1421cad7b5cbdd1
15e010037a6ee2
hex6e2bf48b21f3

121135065407987 has 2 divisors, whose sum is σ = 121135065407988. Its totient is φ = 121135065407986.

The previous prime is 121135065407963. The next prime is 121135065408031. The reversal of 121135065407987 is 789704560531121.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 121135065407987 - 234 = 121117885538803 is a prime.

It is not a weakly prime, because it can be changed into another prime (121135065407287) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60567532703993 + 60567532703994.

It is an arithmetic number, because the mean of its divisors is an integer number (60567532703994).

It is a 1-persistent number, because it is pandigital, but 2⋅121135065407987 = 242270130815974 is not.

Almost surely, 2121135065407987 is an apocalyptic number.

121135065407987 is a deficient number, since it is larger than the sum of its proper divisors (1).

121135065407987 is an equidigital number, since it uses as much as digits as its factorization.

121135065407987 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 12700800, while the sum is 59.

The spelling of 121135065407987 in words is "one hundred twenty-one trillion, one hundred thirty-five billion, sixty-five million, four hundred seven thousand, nine hundred eighty-seven".