12114005443 has 4 divisors (see below), whose sum is σ = 12117790728. Its totient is φ = 12110220160.

The previous prime is 12114005441. The next prime is 12114005471. The reversal of 12114005443 is 34450041121.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 12114005443 - 2¹ = 12114005441 is a prime.

It is a super-3 number, since 3×12114005443³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114005441) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1887838 + ... + 1894243.

It is an arithmetic number, because the mean of its divisors is an integer number (3029447682).

Almost surely, 2^12114005443 is an apocalyptic number.

12114005443 is a deficient number, since it is larger than the sum of its proper divisors (3785285).

12114005443 is an equidigital number, since it uses as much as digits as its factorization.

12114005443 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 3785284.

The product of its (nonzero) digits is 1920, while the sum is 25.

Adding to 12114005443 its reverse (34450041121), we get a palindrome (46564046564).

The spelling of 12114005443 in words is "twelve billion, one hundred fourteen million, five thousand, four hundred forty-three".