Base | Representation |
---|---|
bin | 10001101000001101010… |
… | …101001110000111010010 |
3 | 11021210211212011220020111 |
4 | 101220031111032013102 |
5 | 124321424014202424 |
6 | 2324302253231534 |
7 | 153343505610154 |
oct | 21501525160722 |
9 | 4253755156214 |
10 | 1211404444114 |
11 | 427832255817 |
12 | 176940a925aa |
13 | 8a30924b6a7 |
14 | 428bcdd8ad4 |
15 | 217a101a194 |
hex | 11a0d54e1d2 |
1211404444114 has 4 divisors (see below), whose sum is σ = 1817106666174. Its totient is φ = 605702222056.
The previous prime is 1211404444111. The next prime is 1211404444123. The reversal of 1211404444114 is 4114444041121.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 1200849963889 + 10554480225 = 1095833^2 + 102735^2 .
It is a super-3 number, since 3×12114044441143 (a number of 37 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (1211404444111) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 302851111027 + ... + 302851111030.
Almost surely, 21211404444114 is an apocalyptic number.
1211404444114 is a deficient number, since it is larger than the sum of its proper divisors (605702222060).
1211404444114 is an equidigital number, since it uses as much as digits as its factorization.
1211404444114 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 605702222059.
The product of its (nonzero) digits is 8192, while the sum is 31.
Adding to 1211404444114 its reverse (4114444041121), we get a palindrome (5325848485235).
The spelling of 1211404444114 in words is "one trillion, two hundred eleven billion, four hundred four million, four hundred forty-four thousand, one hundred fourteen".
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