Base | Representation |
---|---|
bin | 11011100010110101101011… |
… | …011111111011000110011011 |
3 | 120212221000000101200002022101 |
4 | 123202311223133323012123 |
5 | 111334234444131124311 |
6 | 1105351323135304231 |
7 | 34342113510114460 |
oct | 3342655337730633 |
9 | 525830011602271 |
10 | 121141356114331 |
11 | 35665840417a93 |
12 | 1170600b07b077 |
13 | 527977220b8c7 |
14 | 21cb3b6c71667 |
15 | e01270bb4ec1 |
hex | 6e2d6b7fb19b |
121141356114331 has 8 divisors (see below), whose sum is σ = 138474058688000. Its totient is φ = 103815352180008.
The previous prime is 121141356114287. The next prime is 121141356114349. The reversal of 121141356114331 is 133411653141121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is not a de Polignac number, because 121141356114331 - 27 = 121141356114203 is a prime.
It is a super-3 number, since 3×1211413561143313 (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.
It is not an unprimeable number, because it can be changed into a prime (121141356114431) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 1674621081 + ... + 1674693418.
It is an arithmetic number, because the mean of its divisors is an integer number (17309257336000).
Almost surely, 2121141356114331 is an apocalyptic number.
121141356114331 is a deficient number, since it is larger than the sum of its proper divisors (17332702573669).
121141356114331 is an equidigital number, since it uses as much as digits as its factorization.
121141356114331 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3349319673.
The product of its digits is 25920, while the sum is 37.
The spelling of 121141356114331 in words is "one hundred twenty-one trillion, one hundred forty-one billion, three hundred fifty-six million, one hundred fourteen thousand, three hundred thirty-one".
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