12114241131 has 4 divisors (see below), whose sum is σ = 16152321512. Its totient is φ = 8076160752.

The previous prime is 12114241121. The next prime is 12114241171. The reversal of 12114241131 is 13114241121.

It is a semiprime because it is the product of two primes.

It is not a de Polignac number, because 12114241131 - 2⁶ = 12114241067 is a prime.

It is a super-3 number, since 3×12114241131³ (a number of 31 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 12114241098 and 12114241107.

It is not an unprimeable number, because it can be changed into a prime (12114241121) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 2019040186 + ... + 2019040191.

It is an arithmetic number, because the mean of its divisors is an integer number (4038080378).

Almost surely, 2^12114241131 is an apocalyptic number.

12114241131 is a deficient number, since it is larger than the sum of its proper divisors (4038080381).

12114241131 is an equidigital number, since it uses as much as digits as its factorization.

12114241131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 4038080380.

The product of its digits is 192, while the sum is 21.

Adding to 12114241131 its reverse (13114241121), we get a palindrome (25228482252).

The spelling of 12114241131 in words is "twelve billion, one hundred fourteen million, two hundred forty-one thousand, one hundred thirty-one".