Base | Representation |
---|---|
bin | 10110100100001000… |
… | …01100110110001011 |
3 | 1011021021002201110102 |
4 | 23102010030312023 |
5 | 144302222014042 |
6 | 5322030240015 |
7 | 606126302315 |
oct | 132204146613 |
9 | 34237081412 |
10 | 12114251147 |
11 | 51571a7209 |
12 | 242105600b |
13 | 11b0a27b5b |
14 | 82cc7c7b5 |
15 | 4ad7dcb32 |
hex | 2d210cd8b |
12114251147 has 2 divisors, whose sum is σ = 12114251148. Its totient is φ = 12114251146.
The previous prime is 12114251143. The next prime is 12114251197. The reversal of 12114251147 is 74115241121.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 12114251147 - 22 = 12114251143 is a prime.
It is a super-3 number, since 3×121142511473 (a number of 31 digits) contains 333 as substring.
It is not a weakly prime, because it can be changed into another prime (12114251143) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6057125573 + 6057125574.
It is an arithmetic number, because the mean of its divisors is an integer number (6057125574).
Almost surely, 212114251147 is an apocalyptic number.
12114251147 is a deficient number, since it is larger than the sum of its proper divisors (1).
12114251147 is an equidigital number, since it uses as much as digits as its factorization.
12114251147 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 2240, while the sum is 29.
Adding to 12114251147 its reverse (74115241121), we get a palindrome (86229492268).
The spelling of 12114251147 in words is "twelve billion, one hundred fourteen million, two hundred fifty-one thousand, one hundred forty-seven".
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