121143120131 has 12 divisors (see below), whose sum is σ = 133250040000. Its totient is φ = 110053418640.

The previous prime is 121143120047. The next prime is 121143120149. The reversal of 121143120131 is 131021341121.

It is not a de Polignac number, because 121143120131 - 2²⁶ = 121076011267 is a prime.

It is a super-3 number, since 3×121143120131³ (a number of 34 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is not an unprimeable number, because it can be changed into a prime (121143120731) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 173756 + ... + 521993.

It is an arithmetic number, because the mean of its divisors is an integer number (11104170000).

Almost surely, 2^121143120131 is an apocalyptic number.

121143120131 is a gapful number since it is divisible by the number (11) formed by its first and last digit.

121143120131 is a deficient number, since it is larger than the sum of its proper divisors (12106919869).

121143120131 is a wasteful number, since it uses less digits than its factorization.

121143120131 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 697210 (or 697199 counting only the distinct ones).

The product of its (nonzero) digits is 144, while the sum is 20.

Adding to 121143120131 its reverse (131021341121), we get a palindrome (252164461252).

The spelling of 121143120131 in words is "one hundred twenty-one billion, one hundred forty-three million, one hundred twenty thousand, one hundred thirty-one".