Base | Representation |
---|---|
bin | 111000011010010110… |
… | …0101101100011010001 |
3 | 102120200200100020002222 |
4 | 1300310230231203101 |
5 | 3441100131023213 |
6 | 131352531350425 |
7 | 11516020245404 |
oct | 1606454554321 |
9 | 376620306088 |
10 | 121143220433 |
11 | 4741620a5a4 |
12 | 1b58a752415 |
13 | b567cbb671 |
14 | 5c130d5d3b |
15 | 3240527808 |
hex | 1c34b2d8d1 |
121143220433 has 8 divisors (see below), whose sum is σ = 122722240320. Its totient is φ = 119574421200.
The previous prime is 121143220403. The next prime is 121143220439. The reversal of 121143220433 is 334022341121.
It is a sphenic number, since it is the product of 3 distinct primes.
It is a cyclic number.
It is not a de Polignac number, because 121143220433 - 216 = 121143154897 is a prime.
It is a super-3 number, since 3×1211432204333 (a number of 34 digits) contains 333 as substring.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (121143220439) by changing a digit.
It is a polite number, since it can be written in 7 ways as a sum of consecutive naturals, for example, 2531303 + ... + 2578716.
It is an arithmetic number, because the mean of its divisors is an integer number (15340280040).
Almost surely, 2121143220433 is an apocalyptic number.
It is an amenable number.
121143220433 is a deficient number, since it is larger than the sum of its proper divisors (1579019887).
121143220433 is a wasteful number, since it uses less digits than its factorization.
121143220433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 5110327.
The product of its (nonzero) digits is 3456, while the sum is 26.
Adding to 121143220433 its reverse (334022341121), we get a palindrome (455165561554).
The spelling of 121143220433 in words is "one hundred twenty-one billion, one hundred forty-three million, two hundred twenty thousand, four hundred thirty-three".
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