121144241322033 has 4 divisors (see below), whose sum is σ = 161525655096048. Its totient is φ = 80762827548020.

The previous prime is 121144241322029. The next prime is 121144241322043. The reversal of 121144241322033 is 330223142441121.

121144241322033 is digitally balanced in base 4, because in such base it contains all the possibile digits an equal number of times.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 121144241322033 - 2² = 121144241322029 is a prime.

It is a super-3 number, since 3×121144241322033³ (a number of 43 digits) contains 333 as substring. Note that it is a super-d number also for d = 2.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 121144241321985 and 121144241322003.

It is not an unprimeable number, because it can be changed into a prime (121144241322043) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20190706887003 + ... + 20190706887008.

It is an arithmetic number, because the mean of its divisors is an integer number (40381413774012).

Almost surely, 2^{121144241322033} is an apocalyptic number.

It is an amenable number.

121144241322033 is a deficient number, since it is larger than the sum of its proper divisors (40381413774015).

121144241322033 is an equidigital number, since it uses as much as digits as its factorization.

121144241322033 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 40381413774014.

The product of its (nonzero) digits is 27648, while the sum is 33.

Adding to 121144241322033 its reverse (330223142441121), we get a palindrome (451367383763154).

The spelling of 121144241322033 in words is "one hundred twenty-one trillion, one hundred forty-four billion, two hundred forty-one million, three hundred twenty-two thousand, thirty-three".