12114443401 has 4 divisors (see below), whose sum is σ = 12115958400. Its totient is φ = 12112928404.

The previous prime is 12114443399. The next prime is 12114443443. The reversal of 12114443401 is 10434441121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 12114443401 - 2¹ = 12114443399 is a prime.

It is a super-3 number, since 3×12114443401³ (a number of 31 digits) contains 333 as substring.

It is a Duffinian number.

It is not an unprimeable number, because it can be changed into a prime (12114443101) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 745441 + ... + 761518.

It is an arithmetic number, because the mean of its divisors is an integer number (3028989600).

Almost surely, 2^12114443401 is an apocalyptic number.

It is an amenable number.

12114443401 is a deficient number, since it is larger than the sum of its proper divisors (1514999).

12114443401 is an equidigital number, since it uses as much as digits as its factorization.

12114443401 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1514998.

The product of its (nonzero) digits is 1536, while the sum is 25.

Adding to 12114443401 its reverse (10434441121), we get a palindrome (22548884522).

The spelling of 12114443401 in words is "twelve billion, one hundred fourteen million, four hundred forty-three thousand, four hundred one".