Base | Representation |
---|---|
bin | 111000011010100011… |
… | …1011101001111010011 |
3 | 102120201011112102111101 |
4 | 1300311013131033103 |
5 | 3441103424402012 |
6 | 131353341525231 |
7 | 11516133656014 |
oct | 1606507351723 |
9 | 376634472441 |
10 | 121150231507 |
11 | 4741a169078 |
12 | 1b590b73817 |
13 | b5695a4926 |
14 | 5c13ddd00b |
15 | 3240e5ed57 |
hex | 1c351dd3d3 |
121150231507 has 2 divisors, whose sum is σ = 121150231508. Its totient is φ = 121150231506.
The previous prime is 121150231471. The next prime is 121150231529. The reversal of 121150231507 is 705132051121.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-121150231507 is a prime.
It is not a weakly prime, because it can be changed into another prime (121150031507) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 60575115753 + 60575115754.
It is an arithmetic number, because the mean of its divisors is an integer number (60575115754).
Almost surely, 2121150231507 is an apocalyptic number.
121150231507 is a deficient number, since it is larger than the sum of its proper divisors (1).
121150231507 is an equidigital number, since it uses as much as digits as its factorization.
121150231507 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 2100, while the sum is 28.
Adding to 121150231507 its reverse (705132051121), we get a palindrome (826282282628).
The spelling of 121150231507 in words is "one hundred twenty-one billion, one hundred fifty million, two hundred thirty-one thousand, five hundred seven".
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