Base | Representation |
---|---|
bin | 1011000001001100000000… |
… | …1001101111010000011011 |
3 | 1120220012000101020110101020 |
4 | 2300103000021233100123 |
5 | 3041443041034144201 |
6 | 41433322455253523 |
7 | 2360165530044600 |
oct | 260230011572033 |
9 | 46805011213336 |
10 | 12115031553051 |
11 | 3950a57523219 |
12 | 1437b8367a2a3 |
13 | 69b59a4451cb |
14 | 2dc5291186a7 |
15 | 160216b03a36 |
hex | b04c026f41b |
12115031553051 has 12 divisors (see below), whose sum is σ = 18790661184552. Its totient is φ = 6922875173088.
The previous prime is 12115031553019. The next prime is 12115031553089. The reversal of 12115031553051 is 15035513051121.
It is not a de Polignac number, because 12115031553051 - 25 = 12115031553019 is a prime.
It is a super-3 number, since 3×121150315530513 (a number of 40 digits) contains 333 as substring.
It is not an unprimeable number, because it can be changed into a prime (12115031563051) by changing a digit.
It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 41207590170 + ... + 41207590463.
It is an arithmetic number, because the mean of its divisors is an integer number (1565888432046).
Almost surely, 212115031553051 is an apocalyptic number.
12115031553051 is a deficient number, since it is larger than the sum of its proper divisors (6675629631501).
12115031553051 is an equidigital number, since it uses as much as digits as its factorization.
12115031553051 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 82415180650 (or 82415180643 counting only the distinct ones).
The product of its (nonzero) digits is 11250, while the sum is 33.
The spelling of 12115031553051 in words is "twelve trillion, one hundred fifteen billion, thirty-one million, five hundred fifty-three thousand, fifty-one".
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