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12118881497 is a prime number
BaseRepresentation
bin10110100100101011…
…10111010011011001
31011021120210222002212
423102111313103121
5144304413201442
65322313404505
7606213536012
oct132225672331
934246728085
1012118881497
11515987a048
122422709735
1311b19895c8
1482d726009
154ade04a82
hex2d25774d9

12118881497 has 2 divisors, whose sum is σ = 12118881498. Its totient is φ = 12118881496.

The previous prime is 12118881457. The next prime is 12118881581. The reversal of 12118881497 is 79418881121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11163824281 + 955057216 = 105659^2 + 30904^2 .

It is a cyclic number.

It is not a de Polignac number, because 12118881497 - 26 = 12118881433 is a prime.

It is a super-2 number, since 2×121188814972 (a number of 21 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (12118881457) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (19) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 6059440748 + 6059440749.

It is an arithmetic number, because the mean of its divisors is an integer number (6059440749).

Almost surely, 212118881497 is an apocalyptic number.

It is an amenable number.

12118881497 is a deficient number, since it is larger than the sum of its proper divisors (1).

12118881497 is an equidigital number, since it uses as much as digits as its factorization.

12118881497 is an odious number, because the sum of its binary digits is odd.

The product of its digits is 258048, while the sum is 50.

The spelling of 12118881497 in words is "twelve billion, one hundred eighteen million, eight hundred eighty-one thousand, four hundred ninety-seven".