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1212013320313 is a prime number
BaseRepresentation
bin10001101000110001100…
…111111001100001111001
311021212102021220000100211
4101220301213321201321
5124324200402222223
62324442523431121
7153364551145345
oct21506147714171
94255367800324
101212013320313
11428014a16494
12176a909854a1
138a3a5434473
1442939c12625
15217d96dcd0d
hex11a319f9879

1212013320313 has 2 divisors, whose sum is σ = 1212013320314. Its totient is φ = 1212013320312.

The previous prime is 1212013320293. The next prime is 1212013320347. The reversal of 1212013320313 is 3130233102121.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1006303903609 + 205709416704 = 1003147^2 + 453552^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-1212013320313 is a prime.

It is a super-2 number, since 2×12120133203132 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1212013327313) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006660156 + 606006660157.

It is an arithmetic number, because the mean of its divisors is an integer number (606006660157).

Almost surely, 21212013320313 is an apocalyptic number.

It is an amenable number.

1212013320313 is a deficient number, since it is larger than the sum of its proper divisors (1).

1212013320313 is an equidigital number, since it uses as much as digits as its factorization.

1212013320313 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 648, while the sum is 22.

Adding to 1212013320313 its reverse (3130233102121), we get a palindrome (4342246422434).

The spelling of 1212013320313 in words is "one trillion, two hundred twelve billion, thirteen million, three hundred twenty thousand, three hundred thirteen".