Base | Representation |
---|---|
bin | 10001101000110001100… |
… | …111111001100001111001 |
3 | 11021212102021220000100211 |
4 | 101220301213321201321 |
5 | 124324200402222223 |
6 | 2324442523431121 |
7 | 153364551145345 |
oct | 21506147714171 |
9 | 4255367800324 |
10 | 1212013320313 |
11 | 428014a16494 |
12 | 176a909854a1 |
13 | 8a3a5434473 |
14 | 42939c12625 |
15 | 217d96dcd0d |
hex | 11a319f9879 |
1212013320313 has 2 divisors, whose sum is σ = 1212013320314. Its totient is φ = 1212013320312.
The previous prime is 1212013320293. The next prime is 1212013320347. The reversal of 1212013320313 is 3130233102121.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 1006303903609 + 205709416704 = 1003147^2 + 453552^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1212013320313 is a prime.
It is a super-2 number, since 2×12120133203132 (a number of 25 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (1212013327313) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 606006660156 + 606006660157.
It is an arithmetic number, because the mean of its divisors is an integer number (606006660157).
Almost surely, 21212013320313 is an apocalyptic number.
It is an amenable number.
1212013320313 is a deficient number, since it is larger than the sum of its proper divisors (1).
1212013320313 is an equidigital number, since it uses as much as digits as its factorization.
1212013320313 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 648, while the sum is 22.
Adding to 1212013320313 its reverse (3130233102121), we get a palindrome (4342246422434).
The spelling of 1212013320313 in words is "one trillion, two hundred twelve billion, thirteen million, three hundred twenty thousand, three hundred thirteen".
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