121202020113 has 4 divisors (see below), whose sum is σ = 161602693488. Its totient is φ = 80801346740.

The previous prime is 121202020099. The next prime is 121202020123. The reversal of 121202020113 is 311020202121.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4, and also an emirpimes, since its reverse is a distinct semiprime: 311020202121 = 3 ⋅103673400707.

It is a cyclic number.

It is not a de Polignac number, because 121202020113 - 2¹² = 121202016017 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 121202020092 and 121202020101.

It is not an unprimeable number, because it can be changed into a prime (121202020123) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 20200336683 + ... + 20200336688.

It is an arithmetic number, because the mean of its divisors is an integer number (40400673372).

Almost surely, 2^121202020113 is an apocalyptic number.

It is an amenable number.

121202020113 is a deficient number, since it is larger than the sum of its proper divisors (40400673375).

121202020113 is an equidigital number, since it uses as much as digits as its factorization.

121202020113 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 40400673374.

The product of its (nonzero) digits is 48, while the sum is 15.

Adding to 121202020113 its reverse (311020202121), we get a palindrome (432222222234).

The spelling of 121202020113 in words is "one hundred twenty-one billion, two hundred two million, twenty thousand, one hundred thirteen".